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Count Length Of String And Display It In LC3 Assembly Language Assignment Solution


Write an assembly language assignment program to count length of string and display it in LC3

Requirements and Specifications

Write an assembler program that prompts a user to input some type of string. It can be anything from a famous sentence, a song lyric, saying, etc. Then write and call a function that will count the number of characters entered and return the number of characters entered back to the main program. The main program will then tell the user how many characters they had entered. You don't need to worry about spaces, commas, periods, etc. Everything typed can be considered a character.
Remember, there is a difference between an integer representation of a number and the character representation of a number.i.e. To print the number 31 you need to print the character 3 which is ×33 in ASCII and 1 is x31 in ASCII.
If you initialise any memory locations or registers, make sure you comment that at the beginning of your code.
Screenshots of output
count length of string and display in LC3 assembly language
Source Code
           .ORIG x3000
            ; Prompt user to enter string
            LEA R0, PROMPT ; load address of prompt
            PUTS ; print the prompt
            ; Count characters in string
            JSR COUNTCHARS ; count characters in string
            ; Convert number to ascii
            LEA R4, NUMBER ; load address to save number
            AND R2, R2, #0 ; start in zero
            STR R2, R4, #0 ; save ending zero
CONVNUM AND R2, R2, #0 ; quotient, start in zero
DIV10 ADD R3, R0, #-10 ; compare number with 10
            BRn SAVEDIGIT ; if less than 10, save digit
            ADD R2, R2, #1 ; else, increment quotient
            ADD R0, R3, #0 ; copy subtraction to number
            BR DIV10 ; repeat
SAVEDIGIT LD R3, ASCII0 ; load ascii 0
            ADD R0, R0, R3 ; convert digit to ascii
            ADD R4, R4, #1 ; increment position in converted string
            STR R0, R4, #0 ; save converted digit
            ADD R0, R2, #0 ; copy quotient to R0
            BRp CONVNUM ; if not zero, convert next digit
            ; Print result message
            LEA R0, RESULT ; load address of result string
            PUTS ; print the string
            ; Print number
PRINTDIGIT LDR R0, R4, #0 ; load digit from converted number
            BRz PRINTEND ; if it's zero, end print
            OUT ; else, print digit
            ADD R4, R4, #-1 ; go to previous digit
            BR PRINTDIGIT ; print next digit
PRINTEND HALT ; terminate the program
; Data for main
PROMPT .STRINGZ "Please enter a string: "
RESULT .STRINGZ "Number of characters entered: "
ASCII0 .FILL 48 ; ascii value of '0'
NUMBER .BLKW 10 ; space to save converted number digits
; Function to count characters in a string
; Returns:
; R0 = count of characters
COUNTCHARS ST R7, SAVER7 ; save return address
            AND R2, R2, #0 ; start count in zero
CNTLOOP GETC ; read character
            OUT ; echo on screen
            ADD R1, R0, #-10 ; compare character with enter
            BRz CNTEND ; if equal, end reading string and end count
            ADD R2, R2, #1 ; else, count one more char
            BR CNTLOOP ; count next character
CNTEND ADD R0, R2, #0 ; return count in R0
            LD R7, SAVER7 ; load return address
            RET ; return to calling function
; Data for countchars
SAVER7 .BLKW 1 ; place to save R7