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Online C Programming Homework Helper


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Programming concepts

#include #include typedef struct line{ float m; float b; int count; double *x; double *y; } line; line* new_obj(float slope, float intercept, int c) { line *obj_ptr = (line*)malloc(sizeof(line)); obj_ptr->m = slope; obj_ptr->b = intercept; obj_ptr->count = c; obj_ptr->x = (double*)malloc(sizeof(double)*c); obj_ptr->y = (double*)malloc(sizeof(double)*c); return obj_ptr; } int main() { FILE *inp = fopen("a5input.txt", "r"); if(inp == NULL) { printf("File cannot be opened. Please check and run again!"); exit(1); } float slope, intercept; int c; fscanf(inp, "%f %f", &slope, &intercept); fscanf(inp, "%d", &c); line *obj_ptr = new_obj(slope, intercept, c); for(int i = 0; i< c; ++i) fscanf(inp, "%lf", &obj_ptr->x[i]); for(int i = 0; i< c; ++i) obj_ptr->y[i] = obj_ptr->m * obj_ptr->x[i] + obj_ptr->b; FILE *out = fopen("a5output-mercedes-ramon.txt", "w"); fprintf(out, "Slope = %f \nIntercept = %f\n", obj_ptr->m, obj_ptr->b); for(int i = 0; icount; ++i) { char sign1 = '+', sign2 = '+'; if(obj_ptr->x[i] < 0) sign1 = '-'; if(obj_ptr->y[i] < 0) sign2 = '-'; fprintf(out, "X%d = %c%8lf\t\tY%d = %c%8lf\n", i+1, sign1, obj_ptr->x[i], i+1, sign2, obj_ptr->y[i]); } fclose(inp); fclose(out); free(obj_ptr->x); free(obj_ptr->y); free(obj_ptr); return 0; } Slope = 2.000000 Intercept = 5.000000 X1 = +1.000000 Y1 = +7.000000 X2 = +2.000000 Y2 = +9.000000 X3 = +4.000000 Y3 = +13.000000 X4 = +8.000000 Y4 = +21.000000 X5 = +16.000000 Y5 = +37.000000 X6 = +31.000000 Y6 = +67.000000 #include #include #include #include #include #include #define ERROR -249852452 #define EXIT -973845634 #define CLEAR -3596893563 float var[10]; int var_ind = 0; void clear_storage_variables() { for(int i = 0; i< 10; ++i) var[i] = -1; } void store_var(float a) { if(var_ind != 10) var[var_ind++] = a; else printf("MEMORY FULL!\n"); } float recall_var() { if(var_ind != 0) return var[--var_ind]; printf("MEMORY EMPTY!\n"); return CLEAR; } float input_operand() { char input[10]; printf("Enter a number: "); scanf("%s", input); float num; if(isalpha(input[0])) { if(strcmp(input,"pi") == 0) num= 3.14159; else if(strcmp(input,"e") == 0) num= 2.7182; else if(strcmp(input,"rcl") == 0) { num = recall_var(); return num; } else if(strcmp(input,"c") == 0) { printf("0\n"); return CLEAR; } else if(strcmp(input,"ca") == 0) { clear_storage_variables(); return CLEAR; } else if(strcmp(input,"q") == 0) return EXIT; } else { sscanf(input, "%f", &num); } return num; } char* input_operator() { char *op = (char *)malloc(sizeof(char)*5); printf("Enter the operation to perform: "); scanf("%s",op); return op; } float compute(float a, float b, char op) { switch(op) { case '+': return a+b; case '-': return a-b; case '*': return a*b; case '/': if(b==0) return ERROR; return a/b; case '^': return pow(a,b); } return 0; } float calc(float a, char *op) { if(strcmp(op,"sto")==0) { store_var(a); return CLEAR; } if(strcmp(op,"sin")==0) return sin(a); if(strcmp(op,"cos")==0) return cos(a); if(strcmp(op,"tan")==0) { if(a==90) return ERROR; return tan(a); } if(strcmp(op,"arcsin")==0) return asin(a); if(strcmp(op,"arccos")==0) return acos(a); if(strcmp(op,"arctan")==0) return atan(a); if(strcmp(op,"root")==0) return sqrt(a); if(strcmp(op,"abs")==0) return abs(a); if(strcmp(op,"inv")==0) return 1/a; if(strcmp(op,"log")==0) { if(a==0) return ERROR; return log(a); } if(strcmp(op,"log2")==0) { if(a==0) return ERROR; return log2(a); } return 0; } int main() { FILE *out = fopen("output.txt", "w"); fprintf(out, "CALCULATOR\n"); clear_storage_variables(); while(1) { float a = input_operand(); if(a == CLEAR) continue; if(a == EXIT) break; if(strcmp(op,"+") == 0 || strcmp(op,"-") == 0 || strcmp(op,"*") == 0 || strcmp(op,"/") == 0 || strcmp(op,"^") == 0) { float b = input_operand(); if(b == CLEAR) continue; if(b == EXIT) break; float ans = compute(a, b, op[0]); if(ans == ERROR) { printf("%6.3f %c\n%6.3f =\nerror\n", a, op[0], b); fprintf(out, "%6.3f %c\n%6.3f =\nerror\n", a, op[0], b); } else { printf("%6.3f %c\n%6.3f =\n%6.3f\n", a, op[0], b, ans); fprintf(out, "%6.3f %c\n%6.3f =\n%6.3f\n", a, op[0], b, ans); } } else { float ans = calc(a, op); if(ans == CLEAR) continue; if(ans == ERROR) { printf("%s %6.3f =\n%error\n", op, a); fprintf(out, "%s %6.3f =\n%error\n", op, a); } printf("%s %6.3f =\n%6.3f\n", op, a, ans); fprintf(out, "%s %6.3f =\n%6.3f\n", op, a, ans); } } fclose(out); return 0; }

Using C for threading programming

#include #include #include #include #include #define MAX_CUSM_NUM 100 using namespace std; // this is the time of the thread. Managed by the main function. int ticks = 0; // calculate number of finished customers. int finished = 0; // the served_sem used to control the output finished from race condidition of // reading and writing sem_tserved_sem; // the assist_sem used to control the waking of assistants threads static sem_tassist_sem; // the seats_sem used to control the 4 seats static sem_tseats_sem; // the cout_sem used to control the output to the stdout static sem_tcout_sem; // struct of customer struct customer{ int cid; int arrival_time; int service_time; }; /** * This function simulates the serving of the customer. It is called when the * waiting thread that this worker should be served. It just waits to the * serving time to end. We can call this "The Assistant thread" * @param customer_ptrcustomer_ptr the customer to be decided for * @return NULL */ void* customer_serving_thread(void *customer_ptr){ customer *c= (customer*)(customer_ptr); sem_wait(&cout_sem); cout<< "Time " << ticks << ": Customer " << c->cid<< " starts" <service_time); sem_post(&assist_sem); // release the assistant sem_wait(&cout_sem); cout<< "Time " << ticks << ": Customer " << c->cid<< " done" <arrival_time != ticks); sem_wait(&cout_sem); cout<< "Time " << ticks << ": Customer " << c->cid<< " arrives" <cid<< " leaves" <>cid) { customer *c = new customer(); c->cid = cid; input >> c->arrival_time; input >> c->service_time; // create a waiting thread with this customer. pthread_create(&threads[nThread++],NULL,customer_waiting_thread,c); } // wait for all threads to be done. while(finished