Professional Python Assignment helper
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Professional Python Assignment helper

Austin, USA

Josh, U

Bachelor’s Degree. in Programming, St. Edward’s University, USA


Professional Python Assignment helper


When it comes to seeking help with Python assignment, you want a person who has vast experience in the subject, who won’t reuse other people’s code to build your programs, and who can deliver the end solution within the agreed timeline. I am that guy! I have more than 12 years of experience in Python programming obtained both from the corporate world and from the academic writing industry. For the period I have been working with students, I have learned a lot especially about what professors look for when awarding marks for Java projects. I, therefore, know how to transform your requirements into a valuable solution that will impress your professor. I am also very careful about deadlines, as I am well aware of the penalties that come with late assignment submission. If you feel that I am the Python assignment helper you are looking for, do not hesitate to contact me.

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Mathematical Operations in Python

print("***** QUESTION 1 *****\n"); def factorial(n): """ Recursively calculat the factorial of n """ # Base case if n == 1: return 1 return n*factorial(n-1) def calnWk(n, k): return n**k def calnPk(n ,k): return factorial(n)/factorial(n-k) def calnCk(n, k): return calnPk(n, k)/factorial(k) print("\n***** QUESTION 2 *****\n"); # Use built-in functions to get the coefficient from sympy import * x, y = symbols('x y') exp = (2*x**2-4*y**3)**30 coeff_real = exp.expand().coeff(x**20).coeff(y**60) print("The coefficient calculated using built-in function for x^20*y^60 is " + str(coeff_real)) print("\n***** QUESTION 3 *****\n"); # Now get the coefficient using the functions from Part 1 # The coefficient of x^90 *y^10 can be calculated as a combination, selecting the element 90 from the 100 available elements # Coefficients of x and y: (ax^c + by^d)^n a = 2 b = -4 c = 2 d = 3 n = 30 # k = 20 # coeff_calc = calnCk(n,k)*a**(n-k) *b**k print("The coefficient calculated using the functions from Part 1 for for x^20*y^60 is: " + str(coeff_calc)) """ print("\n***** QUESTION 4 *****\n"); # Create a random 3x3 matrix import numpy as np A = np.random.uniform(low = 0, high = 1, size=(3,3)) # matrix of random integers from 1 to 10 b = np.matrix([[1],[0],[0]]) # Check if Ax = b has a solution print("Matrix A is:\n" + str(A)) print("\nVector b is:\n" + str(b)) x = np.linalg.solve(A,b) print("\nThe solution x for Ax = b is:\n" + str(x))

Calculating jiffies and server latency

import os import time import datetime import logging import pexpect # Program configurations. log_file = "latency.log" server = "" interval = 1 threshold = 250 # Change it to false to save only to log file. print_stdout = True logging.basicConfig(filename=log_file, level=logging.DEBUG, format='%(levelname)s:%(asctime)s:%(message)s') log = logging.getLogger(__name__) if __name__ == "__main__": program_banner = f"Ping Interval: {interval}, Destination: {server} Threshold to Log (msec): {threshold}" if print_stdout: print(program_banner) command = f"ping -i {interval} {server}" child = pexpect.spawn(command) child.timeout = 1200 first_line = True while True: line = child.readline() if not line: break if line.startswith(b"ping: unknown host"): if print_stdout: print("Unknown host: " + server)"Unknown host: " + server) break if first_line: first_line = False continue ping_time = float(line[line.find(b"time=") + 5 : line.find(b" ms")]) line = time.strftime("%m/%d/%Y %H:%M:%S") + ": " + str(ping_time) + " ms" if print_stdout: print(line) if ping_time> threshold:, line + "\n")