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Create A Squid Game Simulation in C++ Assignment Solution.


Ace your C++ assignment by writing a program to create a squid game simulation in C++. Dive into the world of programming as you craft a captivating simulation that mirrors the intense challenges of the squid game. This assignment will not only test your coding skills but also your creativity in designing an engaging virtual environment. Whether you're a seasoned programmer or a beginner, tackling this squid game simulation will surely enhance your proficiency with C++ and leave you with a sense of accomplishment.

Requirements and Specifications

Program to create a squid game simulation in C++ language

Source Code



using namespace std;

// method which checks, if current player can stand in given row

static bool matches(vector& row, int a) {

 // if row is empty, player can stand here

 if (row.empty()) {

  return true;


 // otherwise we check if sum of numbers of current player and previous player in row

 // is a full square

 int sum = row[row.size()-1] + a;

 int sr = sqrt(sum);

  return sr * sr == sum;


// method, which recursively builds all possible configurations

// it returns number of valid configurations which can be obtained from given state

// by adding players, starting from next

static int solveStep(vector> state, int next, int last) {

 // if all necessary players are located in rows, we must check if obtained state is valid

 if (last < next) {

  bool isOk = true;

  // state is valid is there are no empty rows

  for (vector v : state) {

   // setting flag to false, if there is an empty row

   if (v.empty()) {

    isOk = false;




  // if current state is valid, returning 1, otherwise - 0

  return isOk ? 1 : 0;


 // this variable will store number of valid final states, which can be obtained from

 // current one

 int sum = 0;

 // iterating over all rows and trying to add next player to each row

 for (int i = 0; i

  // checking if next player can be put into i-th row

  if (matches(state[i], next)) {

   // if player can be put here, adding it to current state


   // and calling this method recursively for next player

   // summing up the result

   sum += solveStep(state, next+1, last);

   // rollbacking state by deleting added played


   // if this state was empty, skipping further checks, since it will cause duplicating

   if (state[i].empty()) {





 // returning final sum

 return sum;


// the solution approach is straightforward:

// we recursively build all possible configurations without duplicates

static int solve(int x, int n) {

 // we will store current state as 2D matrix (nested vector of ints)

 vector> solution(x);

 // calling recursive method starting with empty state and first player to place

 return solveStep(solution, 1, n);