+1 (315) 557-6473 
Programming Homework Helper
1721 Order Completed
98 % Response Time
61 Reviews
Since 2011
Related Blogs

Do You Need Help with Programming Homework?“How do I pay someone to do programming homework on my behalf.” This question crosses the mind of every scholar who intends to find programming help online. If you have tried searching for an academic assistant over the net of late, you will notice that the...

Read More

Are You Troubled with Your Java Programming Homework?Java programming language was derived from C but is more flexible and compatible with multiple platforms. Java’s true power lies within people’s ability to manipulate the objects and variables within a program, which is why it is considered an obj...

Read More

Tips To Get The Best Out Of Your C++ Programming Homework HelpIf you are seeking C++ homework help online, that means you are not only expecting quality work but also, timely submissions. It’s evident that most homework helping organizations fail to meet the student’s expectations, once in a while. ...

Read More

Programming Homework Helper

Brisbane, Australia

Kennedy H

Master’s Degree in Programming, Australian Catholic University, Brisbane


Online Programming Homework Helper in Australia


Working on programming homework is not easy but with the right guidance, this can be a cakewalk. I started working as a programming homework helper in Australia in 2011 after I realized how draining these tasks can be to students. I had just graduated with a Master’s Degree in Programming and being fresh from campus, I knew the toll programming projects could take on students. I, therefore, decided to seek an opportunity as an academic assistant, and ProgrammingHomeworkHelp.com provided just the platform I needed to provide my services. It’s now almost 9 years since I started and working with students has taught me so much and improved my skills in programming to a large extent. I wish to offer my support to even more students so they can succeed in this academic area and become excellent programmers in the future.

Get Free Quote
0 Files Selected

Linked List and Binary Search

Searching on a linked list

The reason why the linked list cannot achieve an O(log n) is in terms of search is because of how it is built. A linked list by definition is made up of linked nodes that are scattered throughout the memory. This means that these nodes are not contagiously arranged therefore they cannot be accessed through "index" or "subscripts" like an array. Therefore when we search, we have to go through one link through another to go find a target node. There's no way that we can jump directly to the node or skip some other nodes to shorten the search.

A candidate modification in linked lists

Nodes are not duplicated but only references therefore if we have "N" nodes then the space it will take is N too. However, if we need to take account that a "pointer" takes space in memory then we can compute it as N2and this is because for every N there is a pointer to all other Ns. The asymptotic of inserting a node would be O(2n). It takes O(n) to first find the location in the list after which it will take another O(n) again to make the node point to other nodes that appear after and before it. Binary Search on a Modified List One of the requirements of a binary search is that data should be sorted. So right now we have a node that has a previous node and a next node. It will have also have a list of pointers that points to all other previous nodes and another list of pointers that points to the nodes after it. The mainline list should be sorted in ascending order and the list of pointers is also sorted. The pseudocode is as follows:
  1. Set the current node as the head node.
  2. If the current node's data is the value we're looking for then stop, we're done.
  3. If the value we’re looking for is greater than the current nodes’ data.
    1. Get the middle node of the list of pointers after it.
    2. Set the middle node as the current node.
    3. Repeat step 2.
  4. Otherwise, if the value we're looking for is lesser than the current node's data.
    1. Get the middle node of the list of pointers before it.
    2. Set the middle node as the current node.
    3. Repeat step 2.