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Search for palindromic words in a string using 8086 assembly homework help

The assignment deals with writing an 8086 assembly to search for palindromic words in a given string. The program created by our 8086 assembly homework helpers reads an input string consisting of several words separated by spaces. A procedure is used to determine if any word in the input string is a palindrome. The program prints the number of palindromic words found on the input string.
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  • Identifying Palindromic Words in Strings

Identifying Palindromic Words in Strings

; Emu 8086 programming assignment include "emu8086.inc" org 100h PRINTN "Please enter a string:" lea di, string; set up pointer di to the input string mov dx, 100 ; the maximum size of the string that can be retrieved from user input call GET_STRING ; here, cx has the number of characters in a string lea di, string;set up pointer di to input string mov bx, 0 ; bx will be the word length mov dx, 0 ; dx will have the number of palindrome words found findwords: mov al,[di] ; retrieve char from string cmp al, 0 ; see if we reached the end of the string je endsrch ; if so, end loop cmp al, 'A'; see if it's a letter between A and Z jl newWord cmp al, 'Z' jle increment cmp al, 'a' ; see if it's a letter between a and z jl newWord cmp al, 'z' jle increment newWord: cmp bx, 0 ; if we have a word, check if it's a palindrome je skip; else, we don't have a word, skip mov ax, di; save word start in ax sub ax, bx call check palindrome add dx, ax; increment dx if the word was a palindrome skip: mov bx, 0 ; start a new word jmp nextChar increment: inc bx nextChar: inc di; increment di register jmp findwords ; repeat for all characters in a string endsrch: cmp bx, 0 ; if we have a word, check if it's a palindrome je tstcount ; else, we don't have a word, skip mov ax, di ; save word start in ax sub ax, bx call checkPalindrome add dx, ax ; increment dx if the word was a palindrome tstcount: PRINTN " " cmp dx, 0 ; see if we found palindromic words je notfound ; if not, print a not found message PRINT "Found " mov ax, dx ; print the number we found call PRINT_NUM_UNS PRINTN " palindromic words" ret notfound: PRINTN "No palindromic words found" ret ; check if the word starting in ax and length bx is a palindrome ; returns ax = 0 if it's not a palindrome, ax = 1 if it's a palindrome checkPalindrome: push di mov di, ax ; save word start pointer in di mov si, di ; point to last char with si add si, bx dec si chkloop: cmp di, si ; see if the pointers have crossed jge ispal ; if they crossed, it's a palindrome mov al, [di] ; else, compare characters at both ends mov ah, [si] cmp al, ah jne nopal ; if they are not equal, is not a palindrome inc di ; else advance to next character at the front dec si; and advance to the previous character at the end jmp chkloop ispal: ; it's a palindrome, return 1 mov ax, 1 jmp retpal nopal: ; it's no palindrome, return 0 mov ax, 0 retpal: pop di ret ; Program Data string DB 100 dup(?) key equ 37 define_GET_STRING define_PRINT_STRING define_PRINT_NUM_UNS define_PRINT_NUM end